Question
In a completely randomized design, 12 experimental units were used for the first treatment, 15 for...
In a completely randomized design, 12 experimental units were used for the first treatment, 15 for the second treatment, and 20 for the third treatment. Complete the following analysis of variance (to 2 decimals, if necessary). Round p-value to four decimal places. If your answer is zero enter "0".
| Source of Variation | Sum of Squares | Degrees of Freedom | Mean Square | F | p-value |
| Treatments | 1,300 | ||||
| Error | |||||
| Total | 1,800 |
At a .05 level of
significance, is there a significant difference between the
treatments?
The p-value is Selectless than .01between .01 and
.025between .025 and .05between .05 and .10greater than .10
What is your conclusion?
SelectConclude not all treatment means are equalCannot reject the
assumption all treatment means are equal
Homework Answers
Answer #1
Answer :
Treatment 1 = 12
Treatment 2 = 15
Treatment 3 = 20
So,Total treatment n = 47
Degree of freedom df = n - 1 = 47 - 1 = 46
Level of significance 
the table becomes as :
| Source | SS(Sum of square) | DF(Degreeof freedom) | MS(Mean square) | F | P value |
| Treatment | 1300 |
=k - 1 = 3 - 1 = 2 |
= 1300 / 2 = 650 |
= 650 / 11.36 = 57.22 |
0.0001 |
| Error |
= 1800 - 1300 = 500 |
= n - k = 47 - 3 = 44 |
= 500 / 44 = 11.36 |
||
| Total | 1800 |
= 2 + 44 = 46 |
We get p value = 0.0001
i.e p value less than 0.01
So,we reject null hypothesis.
YES,there a significant difference between the treatments.Conclude not all treatment means are equal
Not the answer you're looking for?
Similar Questions
In a completely randomized design, 12 experimental units were used for the first treatment, 15 for...
In a completely randomized design, 12 experimental units were
used for the first treatment, 15 for the second treatment, and 20
for the third treatment. Complete the following analysis of
variance (to 2 decimals, if necessary). If the answer is zero enter
"0".
Source of Variation
Sum of Squares
Degrees of Freedom
Mean Square
F
p-value
Treatments
1,200
Error
Total
1,800
At a .05 level of significance, is there a significant
difference between the treatments?
The -value is - Select...
In a completely randomized design, 12 experimental units were used for the first treatment, 15 for...
In a completely randomized design, 12 experimental units were
used for the first treatment, 15 for the second treatment, and 20
for the third treatment. Complete the following analysis of
variance (to 2 decimals, if necessary). If the answer is zero enter
"0".
Source of Variation
Sum of Squares
Degrees of Freedom
Mean Square
F
p-value
Treatments
1400
Error
Total
1800
At a .05 level of significance, is there a significant
difference between the treatments?
The p-value is - Select...
In a completely randomized design, 12 experimental units were used for the first treatment, 15 for...
In a completely randomized design, 12 experimental units were
used for the first treatment, 15 for the second treatment, and 20
for the third treatment. Complete the following analysis of
variance (to 2 decimals, if necessary). If your answer is zero
enter "0". Source of Variation Sum of Squares Degrees of Freedom
Mean Square F Treatments 1,300 Error Total 2,100 At a .05 level of
significance, is there a significant difference between the
treatments? The p-value is What is your...
The following data are from a completely randomized design. Treatment Treatment Treatment A B C 32...
The following data are from a completely randomized design.
Treatment
Treatment
Treatment
A
B
C
32
46
33
30
45
36
30
46
35
26
48
36
32
50
40
Sample mean
30
47
36
Sample variance
6
4
6.5
At the = .05 level of significance, can we reject
the null hypothesis that the means of the three treatments are
equal?
Compute the values below (to 1 decimal, if necessary).
Sum of Squares, Treatment
Sum of Squares, Error
Mean Squares,...
Consider the experimental results for the following randomized block design. Make the calculations necessary to set...
Consider the
experimental results for the following randomized block design.
Make the calculations necessary to set up the analysis of variance
table.
Treatment
A
B
C
1
10
10
9
2
13
6
6
Blocks
3
18
16
15
4
21
18
19
5
8
8
9
Use = .05 to test for
any significant differences. Show entries to 2 decimals, if
necessary. If your answer is zero enter "0".
Source of
Variation
Sum of
Squares
Degrees of
Freedom
Mean...
In a completely randomized design, 12 experimental units were used for the first treatment, 15 for...
In a completely randomized design, 12 experimental units were
used for the first treatment, 15 for the second treatment, and 20
for the third treatment. Complete the following analysis of
variance (to 2 decimals, if necessary). If the answer is zero enter
"0".
Source of Variation
Sum of Squares
Degrees of Freedom
Mean Square
F
p-value
Treatments
1100
Error
700
44
xx
xxxx
Total
1800
xx
xxx
In a completely randomized design, 10 experimental units were used for the first treatment, 12 for...
In a completely randomized design, 10 experimental units were
used for the first treatment, 12 for the second treatment, and 19
for the third treatment. Sum of Squares due to Treatments and Sum
of Squares Total is computed as 1100 and 1700 respectively. Prepare
the ANOVA table and complete the same (fill out all the cells).
State the Hypotheses. At a .05 level of significance, is there a
significant difference between the treatments? Use both p-Value and
Critical-Value approaches.
Please...
In a completely randomized design, seven experimental units were used for each of the five levels...
In a completely
randomized design, seven experimental units were used for each of
the five levels of the factor. Complete the following ANOVA table
(to 2 decimals, if necessary). Round p-value to four
decimal places. If your answer is zero enter "0".
Source of
Variation
Sum of
Squares
Degrees of
Freedom
Mean Square
F
p-value
Treatments
300
Error
Total
460
What hypotheses are implied in
this problem?
h 0: SelectAll five treatment means are equa or lNot all
five treatment...
To study the effect of temperature on yield in a chemical process, five batches were produced...
To study the effect of temperature on yield in a chemical
process, five batches were produced at each of three temperature
levels. The results follow.
Temperature
50°C
60°C
70°C
31
28
24
21
29
29
33
32
29
36
21
31
29
25
32
Construct an analysis of
variance table (to 2 decimals, if necessary). Round
p-value to four decimal places.
Source of
Variation
Sum of
Squares
Degrees of
Freedom
Mean Square
F
p-value
Treatments
Error
Total
Use a .05...
o study the effect of temperature on yield in a chemical process, five batches were produced...
o study the effect of temperature on yield in a chemical
process, five batches were produced at each of three temperature
levels. The results follow.
Temperature
50°C
60°C
70°C
32
33
29
22
34
34
34
37
34
37
26
36
30
30
37
Construct an analysis of
variance table (to 2 decimals, if necessary). Round
p-value to four decimal places.
Source of
Variation
Sum of
Squares
Degrees of
Freedom
Mean Square
F
p-value
Treatments
Error
Total
Use a .05...
ADVERTISEMENT
Need Online Homework Help?
Get Answers For Free
Most questions answered within 1 hours.
ADVERTISEMENT
Active Questions
asked 9 minutes ago
asked 9 minutes ago
asked 27 minutes ago
asked 27 minutes ago
asked 53 minutes ago
asked 1 hour ago
asked 1 hour ago
asked 1 hour ago
asked 1 hour ago
asked 1 hour ago
asked 1 hour ago
asked 2 hours ago