Sixty college students were surveyed about the number of hours they watch television per week. The sample mean was 6.405 hours with a standard deviation of 5.854. Construct a 99% confidence interval for the mean number of hours of television watched by all college student.
Find the value of z or t, whichever is appropriate. Be sure to draw a bell curve
illustrating
the confidence level.
b)
Find the value of the standard error (SE).
c)
Find the value of the margin of error (ME).
d)
Find the confidence interval.
Solution: a) Find the value of z or t, whichever is appropriate. Be sure to draw a bell curve illustrating the confidence level.
Answer: Since the sample size is greater than 30, so we can use z statistic here. The z critical value at 0.01 significance can be found using the standard normal table and z critical value is given below:
b)Find the value of the standard error (SE).
Answer: The standard error is given below:
c)Find the value of the margin of error (ME).
Answer: The margin of error is:
d) Find the confidence interval.
Answer: The confidence interval is:
Therefore, the 99% confidence interval is
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