Question

1.) Between z=0 and z=-0.32 please give answer in a percent

2.) Between z=0 and z=-0.32 please give answer 4 decimal places

3.) To the right of z=2.01 please give answer 4 decimal place

Answer 1

Using standard normal z-table we find the following probabilities,

1) We want to find, P(-0.32 < Z < 0)

P(-0.32 < Z < 0)

= P(Z < 0) - P(Z < -0.32)

= 0.5000 - 0.3745

= 0.1255

Therefore, required percentage is 12.55%

2) P(-0.32 < Z < 0) = 0.1255

Therefore, the area between z = 0 and z = -0.32 is 0.1255

3) We want to find, P(Z > 2.01)

P(Z > 2.01) = 1 - P(Z < 2.01) = 1 - 0.9778 = 0.0222

=> P(Z > 2.01) = 0.0222

Therefore, the area to the right of z = 2.01 is 0.0222