In a survey, the planning value for the population proportion is p*=.25 . How large a sample should be taken to provide a 95% confidence interval with a margin of error of .06? Round your answer to next whole number.
Solution :
Given that,
= 0.25
1 - = 1 - 0.25= 0.75
margin of error = E = 0.06
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96 ( Using z table )
Sample size = n = (Z/2 / E)2 * * (1 - )
= (1.96 / 0.06)2 * 0.25* 0.75
= 200.08
Sample size =200
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