Question

Conservation management for Yangtze finless porpoises also includes a captive population. In the captive population of 126 porpoises, you determine that the females in the population produce 28 surviving babies each year. On average, 20 porpoises in the captive population die every year. Based on these numbers, and given unlimited space and resources, how many porpoisess would be in your captive population in five years? Ten years? Twenty years? Show all your work.

Female population was never given.

Answer 1

Answer:

Populace of porpoises in year 1 = 126 + 28 - 20

= 134

Populace of porpoises in year 2 = 134 + 20 - 15

= 139

In this way there is a net increment of 5 porpoises every year

In this way ,number of new porpoises following 5 years = 5*5

= 25

In this way ,number of new porpoises following 10 years = 5*10

= 50

In this way ,number of new porpoises following 10 years = 5*20

= 100.

No: porpoises following 5 years = 126 + 25

= 151

No: porpoises following 10 years = 126 + 50

= 176

No: porpoises following multi i.e., 20 year = 126 + 100

= 226