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Suppose the amount of heating oil used annually by households in Ontario is normally distributed with...

Suppose the amount of heating oil used annually by households in Ontario is normally distributed with a mean of 760 liters per household per year and a standard deviation of 150 liters of heating oil per household per year. What is the probability that a randomly selected Ontario household uses more than 570 liters of heating oil per year?

Math   Statistics-And-Probability   
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Answer #1

Given

= 760

= 150

Now calculate p( x > 570)

P(x > 570) = 0.5 + P(0 < z < x-/​​​​​​)

We know that x = 570

= 0.5 + P( 0 < z < 570-760/150)

= 0.5 + P(0 < z < -1.27)

= 0.5 + 0.3980

P( x > 570) = 0.8980

Probability that Ontario household uses more than 570 liter of heating oil per year is 0.8980.

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