Question

A Study found that consumers spend an average of $21 per week in cash without being...

A Study found that consumers spend an average of $21 per week in cash without being aware of where it goes. Assume that the amount of cash spent without being aware it goes is normally distributed and that the standard deviation is $4.

A) what is the probability that a randomly selected will spend more that $23?

P(x>$23)=

round to four decimal places as needed.

B) what is the probability that a randomly selected person will spend between $10 and $18.

P($10<X<$18)=

round to four decimal places as needed.

C) Between what two values will the middle 95% of the amounts of cash spent fall?

The middle 95% of the amounts of cash spent will fall between X=$ and X=$

Round to the nearest cent as needed.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
6) A study found that consumers spend an average of $24 per week in cash without...
6) A study found that consumers spend an average of $24 per week in cash without being aware of where it goes. Assume that the amount of cash spent without being aware of where it goes is normally distributed and that the standard deviation is $6. What is the probability that a randomly selected person will spend between $11 and $23?
5) A study found that consumers spend an average of $24 per week in cash without...
5) A study found that consumers spend an average of $24 per week in cash without being aware of where it goes. Assume that the amount of cash spent without being aware of where it goes is normally distributed and that the standard deviation is $6. What is the probability that a randomly selected person will spend more than $28?
One year consumers spent an average of ​$21 on a meal at a resturant. Assume that...
One year consumers spent an average of ​$21 on a meal at a resturant. Assume that the amount spent on a resturant meal is normally distributed and that the standard deviation is ​$5. Complete parts​ (a) through​ (c) below. a. What is the probability that a randomly selected person spent more than ​$22? ​P(Xgreater than>​$22​)= ​(Round to four decimal places as​ needed.) b. What is the probability that a randomly selected person spent between ​$9 and ​$18? ​P($9less than<Xless than<​$18​)equals=nothing...
One year consumers spent an average of ​$24 on a meal at a resturant. Assume that...
One year consumers spent an average of ​$24 on a meal at a resturant. Assume that the amount spent on a resturant meal is normally distributed and that the standard deviation is ​$4. Complete parts​ (a) through​ (c) below. a. What is the probability that a randomly selected person spent more than ​$26​? ​P(X>​$26​)= ​ b. What is the probability that a randomly selected person spent between ​$15 and ​$22​? ​P($15<X<​$22​)=nothing ​ c. Between what two values will the middle...
One year consumers spent an average of $23 on a meal at a restaurant. Assume that...
One year consumers spent an average of $23 on a meal at a restaurant. Assume that the amount spent on a restaurant meal is normally distributed and that the standard deviation is $6. What is the probability that a randomly selected person spent between $9 and $21? P($9<X<$21)=? (Round to four decimal places as​ needed.) ​
One year consumers spent an average of ​$24 on a meal at a resturant. Assume that...
One year consumers spent an average of ​$24 on a meal at a resturant. Assume that the amount spent on a resturant meal is normally distributed and that the standard deviation is ​$5 Complete parts​ (a) through​ (c) below Between what two values will the middle 95% of the amounts of cash spent​ fall? The middle 95% of the amounts of cash spent will fall between X=$ ​and X=$​
one year consumers spent an average of $22 on a meal at a restaurant. assume that...
one year consumers spent an average of $22 on a meal at a restaurant. assume that the amount spent on a restaurant meal is normally distributed and that the standard deviation is $3. between what two values will the middle 95% of the amount of cash spent fall. the middle 95% of the amounts of cash spent will fall between x=$ and   x =$
A study found that the mean amount of time cars spent in​ drive-throughs of a certain​...
A study found that the mean amount of time cars spent in​ drive-throughs of a certain​ fast-food restaurant was 156.1 seconds. Assuming​ drive-through times are normally distributed with a standard deviation of 33 ​seconds, complete parts​ (a) through​ (d) below. ​(a) What is the probability that a randomly selected car will get through the​ restaurant's drive-through in less than 118 ​seconds? The probability that a randomly selected car will get through the​ restaurant's drive-through in less than 118 seconds is...
A study found that the mean amount of time cars spent in​ drive-throughs of a certain​...
A study found that the mean amount of time cars spent in​ drive-throughs of a certain​ fast-food restaurant was 137.2 seconds. Assuming​ drive-through times are normally distributed with a standard deviation of 30 ​seconds, complete parts​ (a) through​ (d) below. (a) What is the probability that a randomly selected car will get through the​ restaurant's drive-through in less than 99 ​seconds? The probability that a randomly selected car will get through the​ restaurant's drive-through in less than 99 seconds is...
A study found that the mean amount of time cars spent in drive-throughs of a certain...
A study found that the mean amount of time cars spent in drive-throughs of a certain fast-food resturant was 146.5 seconds. Assuming drive-through times are normally distributed with a standard deviation of 33 seconds. A.) What is the probability that a randomly selected car will get through the restaurant's drive-through in less than 102 seconds? _______ (Round to four decimal places as needed). B.) What is the probability that a randomly selected car will spend more than 188 seconds in...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT