Let x be a normal random variable with mean equal to 40 and standard deviation equal to 5
a) P(x>55)=?
b) P(x<49)=?
Solution :
Given that ,
mean = = 40
standard deviation = = 5
(a)
P(x > 55) = 1 - P(x < 55)
= 1 - P((x - ) / < (55 - 40) / 5)
= 1 - P(z < 3)
= 1 - 0.9987
= 0.0013
P(x > 55) = 0.0013
Probability = 0.0013
(b)
P(x < 49) = P((x - ) / < (49 - 40) / 5)
= P(z < 1.8)
Using standard normal table,
P(x < 49) = 0.941
Probability = 0.9641
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