Question

Answer the question for a normal random variable *x* with
mean *μ* and standard deviation *σ* specified below.
(Round your answer to one decimal place.)

*μ* = 38 and *σ* = 8.

Find a value of *x* that has area 0.01 to its right.

Answer #1

Given that,

mean = = 38

standard deviation = = 8

Using standard normal table,

P(Z > z) = 0.01

= 1 - P(Z < z) = 0.01

= P(Z < z) = 1 - 0.01

= P(Z < z ) = 0.99

= P(Z < 2.33) = 0.99

z = 2.33

Using z-score formula,

x = z * +

x = 2.33 * 8 + 38

x = 56.64

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