Answer the question for a normal random variable x with mean μ and standard deviation σ specified below. (Round your answer to one decimal place.)
μ = 38 and σ = 8.
Find a value of x that has area 0.01 to its right.
Given that,
mean = = 38
standard deviation = = 8
Using standard normal table,
P(Z > z) = 0.01
= 1 - P(Z < z) = 0.01
= P(Z < z) = 1 - 0.01
= P(Z < z ) = 0.99
= P(Z < 2.33) = 0.99
z = 2.33
Using z-score formula,
x = z * +
x = 2.33 * 8 + 38
x = 56.64
***please ask if you have any doubts.Happy to help you.Thank you.Please Like.
Get Answers For Free
Most questions answered within 1 hours.