In the planning stage, a sample proportion is estimated as pˆ = 30/50 = 0.60. Use this information to compute the minimum sample size n required to estimate p with 95% confidence if the desired margin of error E = 0.07. What happens to n if you decide to estimate p with 90% confidence? (You may find it useful to reference the z table. Round intermediate calculations to at least 4 decimal places and "z" value to 3 decimal places. Round up your answers to the nearest whole number.)
sample proportion = 30/50 = 0.60
Margin of error (E) = 0.07
We want to find, the sample size for the following confidence level,
i) A 95% confidence level has significance level of 0.05 and critical value is,
Therefore, required sample size is 188
ii) A 90% confidence level has significance level of 0.10 and critical value is,
Therefore, required sample size is 133
NOTE : if wr reduced the confidence level from 95% to 90% then then required sample size gets reduced.
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