Question

In the planning stage, a sample proportion is estimated as pˆ = 30/50 = 0.60. Use this information to compute the minimum sample size n required to estimate p with 95% confidence if the desired margin of error E = 0.07. What happens to n if you decide to estimate p with 90% confidence? (You may find it useful to reference the z table. Round intermediate calculations to at least 4 decimal places and "z" value to 3 decimal places. Round up your answers to the nearest whole number.)

Confidence Level |
n |

95% | |

90% |

Answer #1

Given that,

sample proportion = 30/50 = 0.60

Margin of error (E) = 0.07

We want to find, the sample size for the following confidence level,

i) A 95% confidence level has significance level of 0.05 and critical value is,

Therefore, required sample size is **188**

ii) A 90% confidence level has significance level of 0.10 and critical value is,

Therefore, required sample size is **133**

**NOTE :** if wr reduced the confidence level from
95% to 90% then then required sample size gets reduced.

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