Question

A market research company wishes to know how many energy drinks teenagers drink each week. They want to construct a 80% confidence interval with an error of no more than 0.08. A consultant has informed them that a previous study found the mean to be 7.3 energy drinks per week and found the standard deviation to be 0.7. What is the minimum sample size required to create the specified confidence interval? Round your answer up to the next integer.

Answer 1

Solution

standard deviation ==0.7

Margin of error = E = 0.08

At 80% confidence level the z is ,

= 1 - 80% = 1 - 0.80 = 0.20

/ 2 =0.10

Z/2 = Z0.10 = 1.28

sample size = n = [Z/2* / E] 2

n = ( 1.28*0.7 /0.08 )2

n =125.44

Sample size = n =126