Six dice are rolled calling 6 a success: find the probability of getting ; (a) 3 successes (b) at most 3 successes
Hello Sir/ Mam
Six dice are rolled.
Falling of a die as a 6 is called success.
Hence,
it is a case of binomial distribution where:
p = 1/6
n = 6
Now, we know that:
Hence, using this formula,
p | 16.67% |
n | 6 |
x | |
x | P(x) |
0 | 0.33490 |
1 | 0.40188 |
2 | 0.20094 |
3 | 0.05358 |
4 | 0.00804 |
5 | 0.00064 |
6 | 0.00002 |
(a)
P(3 success) = 0.0536
(b)
P(at most 3 success) = 0.9913
I hope this solves your doubt.
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