Question

Run a regression analysis on the following bivariate set of data
with *y* as the response variable.

x | y |
---|---|

48 | 41.8 |

39.2 | 67.4 |

34.7 | 68.4 |

42.9 | 50.2 |

49 | 50.6 |

45.6 | 57 |

58.7 | 29.7 |

40.5 | 68.4 |

47.4 | 34.7 |

45.7 | 50.9 |

38.9 | 47.7 |

40.9 | 53.6 |

Find the correlation coefficient and report it accurate to three
decimal places.

*r* =

What proportion of the variation in *y* can be explained by
the variation in the values of *x*? Report answer as a
percentage accurate to one decimal place. (If the answer is
0.84471, then it would be 84.5%...you would enter 84.5 without the
percent symbol.)

*r*² = %

Based on the data, calculate the regression line (each value to
three decimal places)

y = x +

13.Predict what value (on average) for the response variable will
be obtained from a value of 40.5 as the explanatory variable. Use a
significance level of α=0.05α=0.05 to assess the strength of the
linear correlation.

What is the predicted response value? (Report answer accurate to
one decimal place.)

*y* =

Answer #1

SUMMARY OUTPUT | |||||||||

Regression Statistics | |||||||||

Multiple R | 0.80159 | ||||||||

R Square | 0.642546 | ||||||||

Adjusted R Square | 0.606801 | ||||||||

Standard Error | 7.857172 | ||||||||

Observations | 12 | ||||||||

ANOVA | |||||||||

df | SS | MS | F | Significance F | |||||

Regression | 1 | 1109.729 | 1109.729 | 17.97564 | 0.001717 | ||||

Residual | 10 | 617.3515 | 61.73515 | ||||||

Total | 11 | 1727.08 | |||||||

Coefficients | Standard Error | t Stat | P-value | Lower 95% | Upper 95% | Lower 95.0% | Upper 95.0% | ||

Intercept | 122.7141 | 16.90241 | 7.260157 | 2.73E-05 | 85.05322 | 160.3751 | 85.05322 | 160.3751 | |

x | -1.60333 | 0.378164 | -4.23977 | 0.001717 | -2.44593 | -0.76073 | -2.44593 | -0.76073 |

Run a regression analysis on the following bivariate set of data
with y as the response variable.
x
y
51.3
17.4
60.8
88.6
37.4
32.9
44.6
53.4
53.7
53.6
52.2
41.5
32.7
28.6
62.4
84.7
47.4
35.7
39.8
33.7
62.1
123
62
83.7
Find the correlation coefficient and report it accurate to three
decimal places.
r = _______
What proportion of the variation in y can be explained by
the variation in the values of x? Report answer as a...

Run a regression analysis on the following bivariate set of data
with y as the response variable.
x
y
28.8
90.1
30.6
139.6
12.6
42.2
18.1
94.8
13.9
28.5
31.9
102.4
-3.9
-13.4
16.7
57.1
11
55.8
16.8
76.3
31.7
80.1
43.5
123.8
Find the correlation coefficient and report it accurate to three
decimal places.
r =
What proportion of the variation in y can be explained by
the variation in the values of x? Report answer as a
percentage...

Run a regression analysis on the following bivariate set of data
with y as the response variable.
x
y
81.1
86
77.5
60.4
92.7
126.5
104
132.5
85
53.1
64.3
95.5
64.6
31.7
39.7
5.7
82.3
121.3
82.4
98.2
29.2
-50.2
34.2
-1
Find the correlation coefficient and report it accurate to three
decimal places.
r =
What proportion of the variation in y can be explained by
the variation in the values of x? Report answer as a
percentage...

Run a regression analysis on the following bivariate set of data
with y as the response variable.
x
y
31
131.5
32.7
88.1
45.9
52.1
51.8
47
65.8
30.1
58.4
36.4
84.5
-92.1
25.3
103.4
49.8
37.5
4.6
127.3
46.6
32.1
75.2
-12.4
Find the correlation coefficient and report it accurate to three
decimal places.
r =
What proportion of the variation in y can be explained by
the variation in the values of x? Report answer as a
percentage...

Run a regression analysis on the following bivariate set of data
with y as the response variable.
x
y
69
25.6
87.1
99.4
80.3
77.2
100.4
148
38.1
4.6
99.7
116.2
82.7
74.6
98
100.3
78.5
65.9
93.4
117.5
82.7
106.4
85
52.3
Find the correlation coefficient and report it accurate to three
decimal places.
r =
What proportion of the variation in y can be explained by
the variation in the values of x? Report answer as a
percentage...

Run a regression analysis on the following bivariate set of data
with y as the response variable.
x
y
16.1
47.3
10.6
42.8
22.4
50.6
33.3
67.6
47.8
61.1
41.4
62.1
30.2
57.9
30.6
53.6
33
57.4
9.7
41.2
19.3
49.6
Verify that the correlation is significant at an α=0.05. If the
correlation is indeed significant, predict what value (on average)
for the explanatory variable will give you a value of 54 on the
response variable.
What is the predicted...

Run a regression analysis on the following bivariate set of data
with y as the response variable.
x
y
107.8
-31.6
73.5
10.7
102
-13.1
44.7
66.8
89.7
2.9
72.7
46.1
76.4
6.7
76.1
22.6
92.2
-0.7
85.4
11.7
98
-8.2
89.8
1.9
66.2
77.1
80.6
21.3
43.4
92.9
Verify that the correlation is significant at an α=0.05α=0.05.
If the correlation is indeed significant, predict what value (on
average) for the explanatory variable will give you a value of -4.3...

Run a regression analysis on the following bivariate set of data
with y as the response variable.
x
y
74.1
53.3
81.3
65.5
64.4
79
102.4
35.8
73
59.4
45.4
110.1
66.4
84.9
73.8
70
52
97.5
70.2
86.9
91.1
43.3
Predict what value (on average) for the response variable will
be obtained from a value of 62.2 as the explanatory variable. Use a
significance level of α=0.05α=0.05 to assess the strength of the
linear correlation.
What is the predicted...

1. Here is a bivariate data set.
x
y
83.7
47.7
73.3
55.5
68.5
42.3
59
43.5
67
41.8
61.6
40.8
64.3
39.2
99.7
71.7
60.8
34.7
69.8
44
86
59.4
47.3
30.8
37.6
20.8
58.6
37.4
57.3
41.1
Find the correlation coefficient and report it accurate to three
decimal places.
r =
2.Run a regression analysis on the following bivariate set of
data with y as the response variable.
x
y
3.8
74.8
54.7
49.8
26.5
64.7
-7.8
86.8...

You run a regression analysis on a bivariate set of data
(n=12n=12). You obtain the regression equation
y=0.631x+48.011y=0.631x+48.011
with a correlation coefficient of r=0.875r=0.875 (which is
significant at α=0.01α=0.01). You want to predict what value (on
average) for the explanatory variable will give you a value of 180
on the response variable.
What is the predicted explanatory value?
x =
(Report answer accurate to one decimal place.)

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