Question

A researcher wishes to test the mean body temperature against the accepted value of 98.6. If...

A researcher wishes to test the mean body temperature against the accepted value of 98.6. If a sample of 26 subjects had an average temperature of 98.4 with a standard deviation of 0.6, what conclusion should be reached? Use a significant level of 0.10

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

H0: = 98.6

Ha: 98.6

Test statistics

t = - / S / sqrt(n )

= 98.4 - 98.6 / 0.6 / sqrt(26)

= -1.70

Critical values at 0.10 level with 25 df = -1.708 , 1.708

Since test statistics falls in non-rejection region, do not reject H0.

We conclude at 0.10 level that we fail to support the claim.

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
It is generally accepted that the mean body temperature is 98.6 degrees. If a sample of...
It is generally accepted that the mean body temperature is 98.6 degrees. If a sample of size 100 resulted in a sample mean of 98.3 degrees with a standard deviation of 0.64 degrees. Does this sample suggest that the mean body temperature is actually lower than 98.6 degrees?
An epidemiologist wishes to check that normal body temperature are indeed 98.6 degrees. They draw a...
An epidemiologist wishes to check that normal body temperature are indeed 98.6 degrees. They draw a random sample of 18 individuals and the sample mean is found to be 98.217 degrees with a standard deviation was .684. What can the epidemiologist conclude about body temperatures?
It is commonly believed that the mean body temperature of a healthy adult is 98.6∘F. You...
It is commonly believed that the mean body temperature of a healthy adult is 98.6∘F. You are not entirely convinced. You believe that it is not 98.6∘F. You collected data using 54 healthy people and found that they had a mean body temperature of 98.26∘F with a standard deviation of 1.16∘F. Use a 0.05 significance level to test the claim that the mean body temperature of a healthy adult is not 98.6∘F. a) Identify the null and alternative hypotheses? H0:...
It is commonly believed that the mean body temperature of a healthy adult is 98.6∘F98.6∘F. You...
It is commonly believed that the mean body temperature of a healthy adult is 98.6∘F98.6∘F. You are not entirely convinced. You believe that it is not 98.6∘F98.6∘F. You collected data using 54 healthy people and found that they had a mean body temperature of 98.22∘F98.22∘F with a standard deviation of 1.17∘F1.17∘F. Use a 0.05 significance level to test the claim that the mean body temperature of a healthy adult is not 98.6∘F98.6∘F. a) Identify the null and alternative hypotheses? H0H0:  (p...
John wishes to study the mean human body temperature. John organizes a simple random sample which...
John wishes to study the mean human body temperature. John organizes a simple random sample which allows him to measure the human body temperature of 45 people at school. His calculations show that his sample has a mean human body temperature of 98.40°F and a standard deviation of 0.62°F. Prior studies indicate that human body temperatures are normally distributed with a standard deviation of 0.50°F. Use the p-value method and a 2% significance level to test the claim that the...
5. Suppose that a doctor claims that 17 year olds have an average body temperature that...
5. Suppose that a doctor claims that 17 year olds have an average body temperature that is higher than the commonly accepted average human temperature of 98.6 degrees Fahrenheit. A simple random statistical sample of 25 people, each of age 17, is selected. The average temperature of the 17 year olds is found to be 98.9 degrees, with standard deviation of 0.6 degrees. Test the doctor’s claim under 5% significant level.
A sample of 100 body temperatures has a mean of 98.6 oF. Assume that population standard...
A sample of 100 body temperatures has a mean of 98.6 oF. Assume that population standard deviation σ is known to be 0.5 oF. Use a 0.05 significance level to test the claim that the mean body temperature of the population is equal to 98.5 oF, as is commonly believed. What is the value of test statistic for this testing? 2.0 –2.0 1.0 3.0
a researcher wishes to test the reaction times of taxi drivers against those of state police...
a researcher wishes to test the reaction times of taxi drivers against those of state police officers. The results of the study showed the 10 taxi drivers had a mean of 0.38 seconds with a population standard deviation of 0.02 seconds. the results of the 9 police officers showed a mean of 0.37 seconds with a population standard deviation of 0.01 seconds. Can we conclude with a 0.02 significant level that the taxi drivers had a slower reaction time? Find...
A medical researcher attempted to learn if a disease is accompanied by an increased in body...
A medical researcher attempted to learn if a disease is accompanied by an increased in body temperature. She measured the body temperature of 12 people diagnosed as having the disease and obtained the following temperatures (in degrees F): 99.3, 99.1, 100.4, 98.4, 98.2, 98.9, 99.7, 100.1, 100.7, 99.0, 98.8, 99.2. Does the mean body temperature of these individuals differ from a hypothesized population mean of 98.6 degree F? Use a two-tailed test and a 0.05 significance level
6. A sample of 200 body temperatures of adults has a mean temperature of 98.10◦F. Suppose...
6. A sample of 200 body temperatures of adults has a mean temperature of 98.10◦F. Suppose the population standard deviation is 0.62◦F. Use a 0.05 significance level to test the claim that the mean body temperature of all adults is equal to 98.6◦F as is commonly believed. Fill in the following information as you test the above claim: State the claim symbolically and the opposite of the claim. H0 : H1 : Teststatistic: P-value: Conclusion:
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT