Problem 4
A web-based travel search engine is designed to complete searches for cruise ships involving price retrieval and scheduling information. You need to analyze how long it takes to complete a typical search. The search time for 2500 randomly selected searches is recorded and determined as the sample mean = 0.94 seconds and sample standard deviation = 0.36 seconds. Choose the most typical value for C and provide the confidence interval.
The most typical value of C is 95%
The 95% confidence interval for population mean is
Given
0.94
s= 0.36
n= 2500
degrees of freedom = n-1 = 2500-1 = 2499
For 95% confidence with 2499 df , critical value of t is , tc =1.96
Thus 95% confidence interval for population mean search time is
=
= (0.93 , 0.95)
Thus 95% confidence interval for population mean search time is ( 0.93 seconds , 0.95 seconds)
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