Use the sample data and confidence level given below to complete parts? (a) through? (d). In a study of cell phone use and brain hemispheric? dominance, an Internet survey was? e-mailed to 2525 subjects randomly selected from an online group involved with ears. 1172 surveys were returned. Construct a 99?% confidence interval for the proportion of returned surveys.
Solution :
Given that,
n = 2525
x = 1172
Point estimate = sample proportion = = x / n = 1172 / 2525 = 0.464
1 - = 0.536
Z/2 = Z 0.05 = 2.576
Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 2.576 * (((0.464 * 0.536) / 2525)
= 0.025
A 99% confidence interval for population proportion p is ,
- E < p < + E
0.464 - 0.025 < p < 0.464 + 0.025
0.439 < p < 0.489
99% confidence interval for the proportion of returned surveys is : (0.439, 0.489)
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