= 1180, = 160, x=1050
We want to find P( x < 1050)
formula is
z = −0.8125
z = -0.81
P( x < 1050) = P (z < -0.81)
find P (z < -0.81) using normal z table e get,
P (z < -0.81) = 0.2083
P( x < 1050) = 0.2083
Probability a student chosen at random will have a SAT score of less than 1050 = 0.2083
Z score outside ( -2 and 2 ) are considered as unusual.
here Z score calculated is ls z =-0.81
Hence, 1050 is not unusual.
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