4. The time that it takes a person to complete a survey is normally distributed with a mean of 18 minutes and a standard deviation of 3.5 minutes. (a) Find the 45’th percentile.
We have given:
Mean = 18 and Standard deviation = 3.5
We have asked to find the 45th percentile, that is Raw score (x).
We know that-
Raw score (x) = Zc * +
Therefore, 45th percentile = Z0.45 * (3.5) + 18
From the Z table we get - Z0.45 = -0.1257
Hence 45th percentile = [( - 0.1257) * (3.5)] + 18
= (-0.4398) + 18
= 17.5602
In excel you can directly use the command =NORMINV(0.45,18,3.5)
= 17.5602
45th percentile = 17.5602 (Rounded to the 4 decimal)
Hope this will help you. Thank you :)
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