Question

Zelda Freeman is working on the release of a new video game and is trying to...

Zelda Freeman is working on the release of a new video game and is trying to understand factors that might drive sales. To try to understand demand better, she decides to analyze data on similar games sold recently at some local retailers. She collects data on the number of units sold during a specified time period, which is her main variable of interest. She hypothesizes that the number of units sold is related to a few other factors, namely the advertising intensity (a composite measure of the amount spent using different media to promote the game), the dollar amount the game was discounted, whether the game was displayed at the end of the aisle or not (1=end of aisle, 0=not end of aisle) and whether the game was released during a holiday period or not (1=holiday period, 0=not a holiday period).

Zelda wants to try to understand the relatiobship between units sold and other variable.

Use the regression results to test to see if the overall model is significant. if any of the independent varible are relation to units sold at the .01 level of significance also find p value.

All other things being equal, how much do you estimate demand (units sold) will change for an extra until of advertising intensity? Rather than give a point estimate, give 95% confidence interval estimate.find left and right ride. if advertising intensity adds explanatory power to the model at the .01level of significance give the p-value that supports your conclusion

SUMMARY OUTPUT
Regression Statistics
Multiple R 0.522893299
R Square 0.273417402
Adjusted R Square 0.248144964
Standard Error 891.0297919
Observations 120
ANOVA
df SS MS F Significance F
Regression 4 34357649.97 8589412 10.81879794 1.7667E-07
Residual 115 91302420.35 793934.1
Total 119 125660070.3
Coefficients Standard Error t Stat P-value Lower 95% Upper 95%
Intercept 979.3604453 376.1497637 2.603645 0.010439915 234.2801567 1724.44073
Discount 66.3876948 58.91028008 1.126929 0.262118525 -50.30223223 183.077622
Holiday? 741.1399017 184.4052416 4.019083 0.000104706 375.8686086 1106.41119
Advertising Intensity 5.947004533 8.277496588 0.718454 0.473934277 -10.44912313 22.3431322
End of Aisle? 760.6675364 182.0413719 4.178542 5.74295E-05 400.0786142 1121.25646

Homework Answers

Answer #1

The p-value for the overall model is 1.7667E-07 that means 0.00000017667 which is less than 0.01 hence the overall model is significant.

The significant variable is Holiday because the p-value corresponding to Holiday in the regression output is 0.000104706 which is less than the level of significance 0.01.

The 95% confidence interval for the unit sold change for an extra unit of advertising intensity is -10.44912313 to 22.3431322 but advertising intensity does not add explanatory power to the model because it is not significant.

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Good luck with your studies!!!

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