An investment has a mean return of 10% and a standard deviation of returns equal to 5%. If the distribution of returns is approximately normal, the probability of obtaining a positive return is:
Select one:
A. 84.13%.
B. 97.72%.
C. 99.87%.
An investment has a mean return of 10% and standard deviation return equal to 5%.
The distribution of returns is approximately normal.
To find the probability of obtaining a positive return.
Let, X be the random variable denoting the return; then X follows a normal distribution with mean 10 and standard deviation of 5.
So, (X-10)/5 ~ standard normal distribution, ie. normal(0,1).
To find P(return is positive)
=P(X>0)
=P(X-10>-10)
=P((X-10)/5>-2)
=P(Z>-2)
Where, Z is the standard normal variate.
=1-phi(-2)
=phi(2)
Where, phi is the distribution function of the standard normal variate.
=0.9772 (from the standard normal table)
So, the corresponding percentage is 0.9772*100=97.72%.
So, the probability of obtaining a positive return is (B) 97.72%
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