Listed below are systolic blood pressure measurements (mm Hg) taken from the right and left arms of the same woman. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Use a 0.01 significance level to test for a difference between the measurements from the two arms. What can be concluded?
Right arm |
145 |
147 |
138 |
138 |
137 |
|
---|---|---|---|---|---|---|
Left arm |
169 |
160 |
184 |
156 |
137 |
what is the Test statistic
what is the p-value?
Right arm | 145 | 147 | 138 | 138 | 137 |
Left arm | 169 | 160 | 184 | 156 | 137 |
Difference | -24 | -13 | -46 | -18 | 0 |
Null hypothesis: There is no difference
Alternate hypothesis: There is significant difference
Now,
t = -2.985
Corresponding p value for two tailed = 0.0558
Since p > alpha ( 0.01 ) we fail to reject the null hypothesis
Get Answers For Free
Most questions answered within 1 hours.