Consider the samples below. Test the following hypothesis at 5% level of significance and find the associated p-value with the test statistic.
|
μ1 - μ2 = 0 | |||||||||||||||||||||||||||||||||||||||||||||
|
μ1 - μ2 ≠ 0
|
assuming independent t test:
Treatment 1
N1: 21
df1 = N - 1 = 21 - 1 = 20
M1: 569.76
SS1: 1557511.81
s21 =
SS1/(N - 1) = 1557511.81/(21-1) =
77875.59
Treatment 2
N2: 21
df2 = N - 1 = 21 - 1 = 20
M2: 367.29
SS2: 1654170.29
s22 =
SS2/(N - 1) = 1654170.29/(21-1) =
82708.51
T-value Calculation
s2p =
((df1/(df1 +
df2)) * s21) +
((df2/(df2 +
df2)) * s22) =
((20/40) * 77875.59) + ((20/40) * 82708.51) = 80292.05
s2M1 =
s2p/N1
= 80292.05/21 = 3823.43
s2M2 =
s2p/N2
= 80292.05/21 = 3823.43
t = (M1 -
M2)/√(s2M1
+ s2M2) =
202.48/√7646.86 = 2.32
Significance Level:
The t-value is 2.31543. The p-value is .025801
Get Answers For Free
Most questions answered within 1 hours.