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The null and alternative hypotheses are,
H0 : μfemales - μmales = 0
H1 : μfemales - μmales ≠ 0
This hypothesis test is a two-tailed test.
Test statistic is,
=> Test statistic = 2.72
i) Since, we don't have a given significance level, we used 0.05.
Therefore, critical values at significance level of 0.05 are, Zcrit = 1.96
Rejection rule : Reject H0, of z < -1.96 or z > 1.96
ii) p-value = 2 * P(Z > 2.72)
=> p-value = 2 * [ 1 - P(Z < 2.72) ]
=> p-value = 2 * [ 1 - 0.9967 ]
=> p-value = 2 * 0.0033
=> p-value = 0.0066
Since, p-value is less than 0.05, we reject H0.
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