The college of business was interested in comparing the attendance for four different class times for a business statistics class. They collected data for the class times (08:00, 10:00, 13:00 and 15:00) for each day (Monday to Friday) of a randomly selected week. Days is the
Select one:
a. has no special name
b. blocking variable
c. treatment variable
d. intersection
e. variation
Suppose we perform ANOVA to test the equality of five means at the 0.05 significance level. If we have 15 observations, what is the critical value?
Select one:
a. 2.145
b. 9.488
c. 1.96
d. 5.96
e. 3.48
Suppose you want to test wheter the average costs of 3 departments in a large company are equal or not. What is the test statistic you have to use?
Select one:
a.
b.
c.
d.
e.
If there are levels of Factor A and levels of Factor B for an ANOVA with interaction, what is the interaction degrees of freedom?
Select one:
a.
b.
c.
d.
e.
If there are levels of Factor A and levels of Factor B for an ANOVA with interaction, what is the interaction degrees of freedom?
Select one:
a.
b.
c.
d.
e.
If there are levels of Factor A and levels of Factor B for an ANOVA with interaction, what is the interaction degrees of freedom?
Select one:
a.
b.
c.
d.
e.
Given the following ANOVA table for treatments each with observations:
Source | Sum of Squares | df | MS | F |
Treatment | a | b | e | g |
Error | c | f | ||
Total | d |
Complete the table
Answer:
i)
Days is the
Blocking variable (option b)
Since each day constitute a full replicate and hence it is a complete block.
ii)
K = 5
N = 15
= 0.05
Therefore,
Critical value = Fk-1,N-k, 0.05 = F4, 10, 0.05 = 3.48
Critical Value = 3.48 (option -e)
iii)
Suppose you want to test whether the average costs of 3 departments in a large company
then, we know to testing 2 or more mean we use ANOVA.
ANOVA use F -test for multiple mean
F =(MST / MSE)
= (Mean sums of square for Group / mean sums of square for Error)
iv)
interaction degrees of freedom = (c-1)*(r-1)
c-1 = levels of Factor A -1
r -1 = levels of Factor B -1
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