Question

Construct the indicated confidence interval for the population mean of each data set. If it is possible to construct a confidence interval, justify the distribution you used. If it is not possible, explain why.

(a) In a random sample of 40 patients, the mean waiting time at a dentist’s office was 20 minutes and the standard deviation was 7.5 minutes. Construct a 95% confidence interval for the population mean.

(b) In a random sample of 20 people, the mean tip that they said they would leave after a $30 meal was $3.75 and the standard deviation was $0.25. Construct a 99% confidence interval for the population mean.

(c) In a random sample of 15 cereal boxes, the mean weight was 11.89 ounces. Assume the weights of the cereal boxes are normally distributed and the population standard deviation is 0.05 ounce. Construct a 90% confidence interval for the population mean.

Answer #1

Thank you.

Construct the indicated confidence interval for the population
mean of each data set. If it is possible to construct a confidence
interval, justify the distribution you used. If it is not
possible, explain why.
***Please provide formulas used, step by step
process, and hand write....thank you so much!
In a random sample of 40 patients, the mean waiting time at a
dentist’s office was 20 minutes and the standard deviation was 7.5
minutes. Construct a 95% confidence interval for the...

Use
the confidenve level and sample data to find a confidence interval
for estimating the population mean. A special research company
randomly selected a simple random sample of 75 birth weights in US.
The mean has of 3433 g with population standard deviation of 495 g
of all birth weights in US. Construct a 90% confidence interval to
estimate the population mean of birth weights
Initial Data:
E(margin of error result value) =
Cl(population mean confidence interval result value)=

Construct a 98% confidence interval for the population
mean. Assume the population has a normal distribution. A random
sample of 40 college students has mean annual earnings of $3200
with a standard deviation of $665.

Use the standard normal distribution or the t-distribution to
construct a 99% confidence interval for the population mean.
Justify your decision. If neither distribution can be used,
explain why. Interpret the results. In a random sample of 13
mortgage institutions, the mean interest rate was 3.59% and the
standard deviation was 0.42%. Assume the interest rates are
normally distributed.
Select the correct choice below and, if necessary, fill in any
answer boxes to complete your choice.
A. The 99% confidence...

For the following questions construct the indicated confidence
interval for the population mean. Note c = confidence level, x ̅
which is equal to the sample mean, s = standard deviation, and n =
sample size
a. c = 0.90, x ̅ = 12.3, s = 1.5, n = 50
b. c = 0.99, x ̅ = 10.5, s = 2.14, n = 45

1) If n=19, ¯xx¯(x-bar)=33, and s=18, construct a confidence
interval at a 80% confidence level. Assume the data came from a
normally distributed population.
Give your answers to one decimal place.
< μμ <
2) You measure 48 backpacks' weights, and find they have a mean
weight of 44 ounces. Assume the population standard deviation is
2.8 ounces. Based on this, construct a 95% confidence interval for
the true population mean backpack weight.
Give your answers as decimals, to two...

10 state which type of
parameter is to be estimated, then construct the confidence
interval
10.
A simple random sample of size 17 has mean x̄ = 8.44
and standard deviation s = 5.38. The population is
normally distributed. Construct a 95% confidence interval for the
population standard deviation
10 state which type of
parameter is to be estimated, then construct the confidence
interval
10.
A simple random sample of size 17 has mean x̄ = 8.44
and standard deviation...

#1. You are to construct a
99% confidence interval of a normally distributed population; the
population standard deviation is known to be 25. A random sample of
size 28 is taken; (i) the sample mean is found to 76 and (ii) the
sample standard deviation was found to be 30. Construct the
Confidence interval. Clearly name the standard distribution you
used (z, or t or F etc.) and show work. (10 points)

Suppose the time a child spends waiting for the bus at the
school bus stop each day is exponentially distributed with a mean
of 2 minutes. Suppose waiting times for the bus are independent
each day. If we look at two days, determine the probability that
the child must wait at most 5 minutes for the bus each of the two
days.
a.
0.9180
b.
0.8426
c.
0.0821
d.
0.2821
e.
0.4179
A sample of 33 boxes of cereal has...

construct a Confidence interval for the population
mean using the information below. Confidence level: 90%, sample
size : 139, standard deviation : 17.54, mean : 106.41.

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