Question

Assume that a procedure yields a binomial distribution with
n=228n=228 trials and the probability of success for one trial is
p=0.29p=0.29.

Find the mean for this binomial distribution.

(Round answer to one decimal place.)

μ=μ=

Find the standard deviation for this distribution.

(Round answer to two decimal places.)

σ=σ=

Use the range rule of thumb to find the minimum usual value μ–2σ
and the maximum usual value μ+2σ.

Enter answer as an interval using square-brackets only with whole
numbers.

usual values =

Answer #1

Assume that a procedure yields a binomial distribution with
n=826n=826 trials and the probability of success for one trial is
p=p=1/12.
Find the mean for this binomial distribution.
(Round answer to one decimal place.)
μ=μ=
Find the standard deviation for this distribution.
(Round answer to two decimal places.)
σ=σ=
The range rule of thumb says that the the minimum usual value is
μ-2σ and the maximum usual value is μ+2σ.
Use this to find the minimum and maximum usual values....

Assume that a procedure yields a binomial distribution with n
trials and the probability of success for one trial is p. Use the
given values of n and p to find the mean μ and standard deviation
σ. Also, use the range rule of thumb to find the minimum usual
value μ−2σ and the maximum usual value μ+2σ.
n=1405, p= 2 / 5

1.
Assume that a procedure yields a binomial distribution with
n=788 trials and the probability of success for one trial is p=0.67
.
Find the mean for this binomial distribution.
(Round answer to one decimal place.)
μ=
Find the standard deviation for this distribution.
(Round answer to two decimal places.)
σ=
Use the range rule of thumb to find the minimum usual value μ-2σ
and the maximum usual value μ+2σ.
Enter answer as an interval using square-brackets round to 4...

Assume that a procedure yields a binomial distribution with n
trials and the probability of success for one trial is p. Use the
given values of n and p to find the mean μ and standard deviation
σ. Also, use the range rule of thumb to find the minimum usual
value μ−2σ and the maximum usual value μ+2σ. Round your answer to
the nearest tenth, if necessary. In an analysis of the 1-Panel TCH
test for marijuana usage, 300 subjects...

Assume that a procedure yields a binomial distribution with n
trials and the probability of success for one trial is p. Use the
given values of n and p to find the mean mu and standard deviation
sigma. Also, use the range rule of thumb to find the minimum usual
value mu minus 2 sigma and the maximum usual value mu plus 2 sigma.
nequals50, pequals0.3
mu equals 15 (Do not round.)
sigma equals (Round to one decimal place as...

Assume that a procedure yields a binomial distribution with n
trials and the probability of success for one trial is p. Use the
given values of n and p to find the mean mu and standard deviation
sigma. Also, use the range rule of thumb to find the minimum usual
value mu minus 2 sigma and the maximum usual value mu plus 2 sigma.
nequals150, pequals0.75 muequals (Do not round.)

Assume that a procedure yields a binomial distribution with n
trials and the probability of success for one trial is p. Use the
given values of n and p to find the mean mu and standard deviation
sigma. Also, use the range rule of thumb to find the minimum usual
value mu minus 2 sigma and the maximum usual value mu plus 2 sigma.
nequals1410, pequals3 divided by 5 muequals nothing (Do not
round.)

Assume that a procedure yields a binomial distribution with
nequals=55 trials and a probability of success of pequals=0.50 Use
a binomial probability table to find the probability that the
number of successes x is exactly 22.

Assume that a procedure yields a binomial distribution with with
n=8 trials and a probability of success of p=0.90. Use a binomial
probability table to find the probability that the number of
successes x is exactly 4.
1. P(4)= ?

question25
Assume that the probability of a being born with Genetic
Condition B is p=p=7/20. A study looks at a random sample of 875
volunteers.
Find the most likely number of the 875 volunteers to have Genetic
Condition B.
(Round answer to one decimal place.)
μ =
Let XX represent the number of volunteers (out of 875) who have
Genetic Condition B. Find the standard deviation for the
probability distribution of XX.
(Round answer to two decimal places.)
σ =...

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