25 randomly selected students took a survey on how long they spent on social media. The mean number of minutes these students spent on social media was 205.1 minutes with a standard deviation of 150 minutes.The population of the time spent on social media is normally distributed. Construct a 98%confidence interval for the population standard deviation of the time students spend on social media.
df = 15 - 1 = 24
T score for 98% confidence interval = t24,0.01 = 2.492
Confidence interval
= (130.34 , 279.86)
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