Question

Use the given values of n and p to find the minimum usual value µ - 2σ and the maximum usual value µ + 2σ. n = 95, p = 0.21 Minimum: 27.89; maximum: 12.01 Minimum: 12.01; maximum: 27.89 Minimum: -11.57; maximum: 51.47 Minimum: 15.98; maximum: 23.92

Answer 1

We have given n = 95 , p = 0.21

We know that-

Mean  = n * p = 95 * 0.21 = 19.95

And standard deviation = = = 3.97

That is we get -   = 19.95 and = 3.97

Hence we get minimum usual value µ - 2σ = 19.95 - (2 * 3.97) = 12.01

and  maximum usual value µ + 2σ = 19.95 +( 2 * 3.97) = 27.89

Hope this will help you. Thank you :)