18)
A laboratory tested 73 chicken eggs and found that the mean amount of cholesterol was 230 milligrams with Η=17.4 milligrams. Construct a 95% confidence interval for the true mean cholesterol content, μ,of all such eggs. A)227mg<μ<235mg B)226mg<μ<234mg C)225mg<μ<233mg D)225mg<μ<234mg
B) 226 mg < μ < 234 mg
Explanation:
Confidence interval for Population mean is given as below:
Confidence interval = Xbar ± t*S/sqrt(n)
From given data, we have
Xbar = 230
S = 17.4
n = 73
df = n – 1 = 72
Confidence level = 95%
Critical t value = 1.9935
(by using t-table)
Confidence interval = Xbar ± t*S/sqrt(n)
Confidence interval = 230 ± 1.9935*17.4/sqrt(73)
Confidence interval = 230 ± 4.0597
Lower limit = 230 - 4.0597 = 225.94
Upper limit = 230 + 4.0597 = 234.06
226 mg < μ < 234 mg
Get Answers For Free
Most questions answered within 1 hours.