Question

1.-To study the effect of temperature on yield in a chemical process, five batches were produced at each of three temperature levels. The results follow.

Temperature
50°C	60°C	70°C
33	30	22
24	30	28
36	35	29
39	23	31
28	27	35

Construct an analysis of variance table. (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.)

Source of Variation	Sum of Squares	Degrees of Freedom	Mean Square	F	p-value
Treatments		2
Error		12
Total		14

2.-A company manufactures printers and fax machines at plants located in Atlanta, Dallas, and Seattle. To measure how much employees at these plants know about quality management, a random sample of 6 employees was selected from each plant and the employees selected were given a quality awareness examination. The examination scores for these 18 employees are shown in the following table. The sample means, sample variances, and sample standard deviations for each group are also provided. Managers want to use these data to test the hypothesis that the mean examination score is the same for all three plants.

	Plant 1 Atlanta	Plant 2 Dallas	Plant 3 Seattle
	86	70	58
	74	74	65
	83	73	63
	76	75	69
	70	69	74
	79	89	67
Sample mean	78	75	66
Sample variance	34.8	52.4	29.6
Sample standard deviation	5.90	7.24	5.44

Set up the ANOVA table for these data. (Round your values for MSE and F to two decimal places, and your p-value to four decimal places.)

Source of Variation	Sum of Squares	Degrees of Freedom	Mean Square	F	p-value
Treatments
Error
Total

3.-Develop the analysis of variance computations for the following completely randomized design. At α = 0.05, is there a significant difference between the treatment means?

	Treatment
	A	B	C
	136	106	91
	121	115	83
	114	126	84
	108	104	102
	130	107	90
	115	110	117
	129	96	109
	99	115	119
		105	97
		96	98
xj	119	108	99
sj2	153.71	82.67	162.67

Find the value of the test statistic. (Round your answer to two decimal places.)___

Find the p-value. (Round your answer to four decimal places.___

Answer 1

Anova: Single Factor
SUMMARY
Groups	Count	Sum	Average	Variance
50°C	5	160	32	36.5
60°C	5	145	29	19.5
70°C	5	145	29	22.5
ANOVA
Source of Variation	SS	df	MS	F	P-value
Between Groups	30	2	15	0.57	0.5784
Within Groups	314	12	26.17
Total	344	14

I have used Excel In excel DATA > DATA ANALYSIS > ANOVA SINGLE FACTOR > SELECT THE DATA > OK