Question

in our Condor Cafe, the Oxnard College Culinary Program offers the most delicious and affortable breakfast and lunch choices among the 152 Community Colleges in California. This week, a random sample of 110 orders were recorded, and 52 orders were for the $5-meals. Please find the 99.9% confidence interval for the true proportion of the orders for the $5-meals.

- Enter your answer as an
**open-interval**(*i.e.*, parentheses) using decimals (not percents) accurate to three decimal places.Confidence interval =

- Express the same answer as a tri-linear inequality using
decimals (not percents) accurate to three decimal places.
<

*p*< - Express the same answer using the point estimate and margin of
error. Give your answers as decimals, to three places.
*p*= ±

Answer #1

We have

A random sample of 110 orders were recorded, and 52 orders were for the $5-meals

and n= 110

we have to find 99.9 % confidence interval,

a)

b) answer as a tri-linear inequality is,

**0.316 < p < 0.629**

e) answer using the point estimate and margin of error is,

A) Express the confidence interval
66.4%<p<81.2%66.4%<p<81.2% in the form of
ˆp±Ep^±E.
_____% ± ± %_____
B) Express the confidence interval 0.69±0.0510.69±0.051 in open
interval form (i.e., (0.155,0.855)).
C) In a survery of 181 households, a Food Marketing Institute found
that 141 households spend more than $125 a week on groceries.
Please find the 98% confidence interval for the true proportion of
the households that spend more than $125 a week on groceries.
Enter your answer as an open-interval
(i.e., parentheses)...

1. If n=290 and X = 232, construct a 99% confidence
interval.
Enter your answer as an open-interval
(i.e., parentheses) using decimals (not percents) accurate
to three decimal places.
Confidence interval =
Express the same answer as a tri-linear inequality using
decimals (not percents) accurate to three decimal places.
< p <
Express the same answer using the point estimate and margin of
error. Give your answers as decimals, to three places.
p = ±±
2. We wish to estimate...

Assume that a sample is used to estimate a population proportion
p. Find the 99.9% confidence interval for a sample of size 391 with
304 successes. Enter your answer as a tri-linear inequality using
decimals (not percents) accurate to three decimal places.

Assume that a sample is used to estimate a population proportion
p. Find the 99% confidence interval for a sample of size
288 with 143 successes. Enter your answer as a tri-linear
inequality using decimals (not percents) accurate to three decimal
places.
_____< p < ______

Assume that a sample is used to estimate a population proportion
p. Find the 98% confidence interval for a sample of size
144 with 62% successes. Enter your answer as a tri-linear
inequality using decimals (not percents) accurate to three decimal
places.
_ < p < _

Assume that a sample is used to estimate a population proportion
p. Find the 90% confidence interval for a sample of size 205 with
10% successes. Enter your answer as a tri-linear inequality using
decimals (not percents) accurate to three decimal places. <
p

Assume that a sample is used to estimate a population proportion
p. Find the 99% confidence interval for a sample of size 224 with
17% successes. Enter your answer as a tri-linear inequality using
decimals (not percents) accurate to three decimal places.
< p <

Assume that a sample is used to estimate a population proportion
p. Find the 95% confidence interval for a sample of size 118 with
82 successes. Enter your answer as a tri-linear inequality using
decimals (not percents) accurate to three decimal places.
answer ____ < p < answer _____

Assume that a sample is used to estimate a population proportion
p. Find the 99% confidence interval for a sample of size
249 with 30 successes. Enter your answer as a tri-linear inequality
using decimals (not percents) accurate to three decimal
places.

Assume that a sample is used to estimate a population proportion
p. Find the 99.5% confidence interval for a sample of size 218 with
36% successes. Enter your answer as a tri-linear inequality using
decimals (not percents) accurate to three decimal places.

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