Question

in our Condor Cafe, the Oxnard College Culinary Program offers the most delicious and affortable breakfast and lunch choices among the 152 Community Colleges in California. This week, a random sample of 110 orders were recorded, and 52 orders were for the $5-meals. Please find the 99.9% confidence interval for the true proportion of the orders for the $5-meals.

1. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places.

   Confidence interval =

2. 
   
3. Express the same answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places.

   < p <

4. 
   
5. Express the same answer using the point estimate and margin of error. Give your answers as decimals, to three places.

   p = ±

Answer 1

We have

A random sample of 110 orders were recorded, and 52 orders were for the $5-meals

and n= 110

we have to find 99.9 % confidence interval,

a)

b) answer as a tri-linear inequality is,

0.316 < p < 0.629

e) answer using the point estimate and margin of error is,