1. A poll of 2234 U.S. adults found that 31% regularly used Facebook as a news source.
Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 90% level of confidence. Round all answers to 2 decimal places.
Margin of Error (as a percentage):
Confidence Interval: % to %
Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 95% level of confidence. Round all answers to 2 decimal places.
Margin of Error (as a percentage):
Confidence Interval: % to %
Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 99% level of confidence. Round all answers to 2 decimal places.
Margin of Error (as a percentage):
Confidence Interval: % to %
The more error we allow, the less precise our estimate. Therefore, as the confidence level increases, the precision of our estimate
2. Assume that a sample is used to estimate a population proportion p. Find the 95% confidence interval for a sample of size 186 with 56% successes.
Confidence interval =
< p <
p = ±±
3. We wish to estimate what percent of adult residents in a
certain county are parents. Out of 600 adult residents sampled, 330
had kids. Based on this, construct a 95% confidence interval for
the proportion p of adult residents who are parents in this
county.
Express your answer in tri-inequality form. Give your answers as
decimals, to three places.
< p < Express the same answer using the point estimate and
margin of error. Give your answers as decimals, to three
places.
p = ±±
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