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Consider the experimental results for the following randomized block design. Make the calculations necessary to set up the analysis of variance table.
Treatments | ||||
---|---|---|---|---|
A | B | C | ||
Blocks | 1 | 10 | 9 | 8 |
2 | 12 | 7 | 5 | |
3 | 18 | 15 | 14 | |
4 | 20 | 18 | 18 | |
5 | 8 | 7 | 8 |
Use α = 0.05 to test for any significant differences.
State the null and alternative hypotheses.
H0: μA ≠ μB ≠
μC
Ha: μA = μB =
μC
H0: Not all the population means are
equal.
Ha: μA = μB =
μC
H0: μA = μB =
μC
Ha: μA ≠ μB ≠
μC
H0: μA = μB =
μC
Ha: Not all the population means are equal.
H0: At least two of the population means are
equal.
Ha: At least two of the population means are
different.
Find the value of the test statistic. (Round your answer to two decimal places.)
Find the p-value. (Round your answer to three decimal places.)
p-value =
State your conclusion.
Reject H0. There is sufficient evidence to conclude that the means of the three treatments are not equal.
Do not reject H0. There is not sufficient evidence to conclude that the means of the three treatments are not equal.
Do not reject H0. There is sufficient evidence to conclude that the means of the three treatments are not equal.
Reject H0. There is not sufficient evidence to conclude that the means of the three treatments are not equal.
from excel": data -data analysis: ANOVA without replication
Source of Variation | SS | df | MS | F | P-value |
block | 304.4 | 4 | 76.1 | 41.14 | 0.000 |
treatment | 25.2 | 2 | 12.6 | 6.81 | 0.019 |
Error | 14.8 | 8 | 1.85 | ||
Total | 344.4 | 14 |
H0: μA = μB =
μC
Ha: Not all the population means are equal.
value of the test statistic =6.81
p-value =0.019
Reject H0. There is sufficient evidence to conclude that the means of the three treatments are not equal.
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