Question

A company decides to offer a monetary incentive for employees who log a specified number of hours spent exercising in an attempt to improve employee health. The average health score (higher = better) of the 45 employees who logged enough hours was 89. The mean health score for all employees was 85, with a standard deviation of 6.1.

12) Is this a directional (one-tailed) or non-directional (two-tailed) study?

13)Calculate the standard error of the mean.

14) Conduct the z-test. Show your work (use at least two decimal places throughout).

What is the z_obt score?

15) What is the z critical value (z_cv)?

16) Write your conclusion in APA format. Don’t forget to include the statistical statement and whether you accept or reject the null hypothesis.

Answer 1

12) This is one directional because alternative hypothesis is Ha:

13)The standard error of the mean.is

14) Conduct the z-test:

the z_obt score= X-mean/S.E= 89-85/0.91

= 4/0.91

=4.395

=4.40

15)The z critical value (z_cv) for one tailed test at 0.05 level of significance is 1.65.

16)Since Calculated value greater than the Critical value therefore we REJECT NULL HYPOTHESIS H0 and conclude that employees who logged enough hours have better score at 0.05 level of significance.