Solution:
Class (1) |
Frequency (f) (2) |
Mid value (x) (3) |
f⋅x (4)=(2)×(3) |
f⋅x2=(f⋅x)×(x) (5)=(4)×(3) |
52.5 - 63.5 | 10 | 58 | 580 | 33640 |
63.5 - 74.5 | 13 | 69 | 897 | 61893 |
74.5 - 85.5 | 28 | 80 | 2240 | 179200 |
85.5 - 96.5 | 15 | 91 | 1365 | 124215 |
96.5 - 107.5 | 14 | 102 | 1428 | 145656 |
--- | --- | --- | --- | --- |
n=80 | ----- | ∑f⋅x=6510 | ∑f⋅x2=544604 |
Answer : Option ( B ) 13.71
Get Answers For Free
Most questions answered within 1 hours.