b)
z value at 2.5% = 1.96
z = (x - mean)/(s/sqrt(n))
1.96 = (x - 3331)/(729/sqrt(24))
x = 3622.66
x = 3623 rounding to whole number
b)
Here, μ = 3331, σ = 148.806501874078, x1 = 3331 and x2 = 5518. We need to compute P(3331<= X <= 5518). The corresponding z-value is calculated using Central Limit Theorem
z = (x - μ)/σ
z1 = (3331 - 3331)/148.806501874078 = 0
z2 = (5518 - 3331)/148.806501874078 = 14.7
Therefore, we get
P(3331 <= X <= 5518) = P((5518 - 3331)/148.806501874078)
<= z <= (5518 - 3331)/148.806501874078)
= P(0 <= z <= 14.7) = P(z <= 14.7) - P(z <= 0)
= 1 - 0.5
= 0.5
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