A simple random sample of size 17 has mean x̄ = 8.44 and standard deviation s = 5.38. The population is normally distributed. Construct a 95% confidence interval for the population standard deviation.
Chi-square critical values at 0.05 level with 16 df = 6.908 , 28.845
95% confidence interval for is
Sqrt [ (n-1) S2 / U) < < Sqrt [ (n-1) S2 / L)
sqrt [ 16 * 5.382 / 28.845 ] < < sqrt [ 16 * 5.382 / 6.908]
4.01 < < 8.19
95% CI is ( 4.01 , 8.19 )
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