Question

Let the probability of success on a Bernoulli trial be 0.21. a. In seven Bernoulli trials, what is the probability that there will be 6 failures? (Do not round intermediate calculations. Round your final answer to 4 decimal places.) b. In seven Bernoulli trials, what is the probability that there will be more than the expected number of failures? (Do not round intermediate calculations. Round your final answer to 4 decimal places.)

Answer 1

This is a binomial distribution question with
n = 7
p = 0.21
q = 1 - p = 0.79
where

a) x = 1(six failure means 1 success in 7 trials)

b) Since we know that

So mean for success is 1.47, means we have to find probability for more than equal to 6 failures, which in turn means less than equal to 1 success

Please hit thumps up if the answer helped you