With a standard deck of 52 playing cards, how many seven-card hands containing exactly one pair of 5's are possible?
standard deck 52 cards
7 card hands
2 of them are 5's while remaining 5 are from remaining 48 cards
P(one pair of 5's in 7 card hand) = ?
P(one pair of 5's in 7 card hand) = n(chose 2 5's out of 4)*n(chose 5 cards out of remaining 48)/n(chose 7 of 52 cards)
P(one pair of 5's in 7 card hand) =
P(one pair of 5's in 7 card hand) =
P(one pair of 5's in 7 card hand) =
P(one pair of 5's in 7 card hand) =
P(one pair of 5's in 7 card hand) =
P(one pair of 5's in 7 card hand) = 0.0768
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