Question

With a standard deck of 52 playing cards, how many seven-card hands containing exactly one pair...

With a standard deck of 52 playing cards, how many seven-card hands containing exactly one pair of 5's are possible?

Homework Answers

Answer #1

standard deck 52 cards

7 card hands

2 of them are 5's while remaining 5 are from remaining 48 cards

P(one pair of 5's in 7 card hand) = ?

P(one pair of 5's in 7 card hand) = n(chose 2 5's out of 4)*n(chose 5 cards out of remaining 48)/n(chose 7 of 52 cards)

P(one pair of 5's in 7 card hand) =

P(one pair of 5's in 7 card hand) =

P(one pair of 5's in 7 card hand) = ​​​​​​​

P(one pair of 5's in 7 card hand) = ​​​​​​​​​​​​​​

P(one pair of 5's in 7 card hand) =

P(one pair of 5's in 7 card hand) = ​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​​0.0768

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