Question

Give a 98% confidence interval, for μ1−μ2μ1-μ2 given the following information.

n1=35n1=35, ¯x1=2.69x¯1=2.69, s1=0.7s1=0.7

n2=40n2=40, ¯x2=3.15x¯2=3.15, s2=0.46s2=0.46

±± Rounded to 2 decimal places

Answer #1

solution:

Given data

1 = 2.69 , S1 = 0.7 , n1 = 35

2 = 3.15 , S2 = 0.46 , n2 = 40

For 98% confidence level , = 1 - CL = 1 - 0.98 = 0.02

Z(/2) = Z(0.01) = 2.33 [using Z distribution table ]

The confidennce interval for difference between two means is given by

CI : (1 - 2 ) ± Z *

: (2.69 - 3.15) ± 2.33 *

: -0.46 ± 0.324

: ( -0.784 , -0.136)

Therefore , 98% confidence interval is **-0.78 <
< -0.14**

:

Give a 99.9% confidence interval, for μ1−μ2μ1-μ2 given the
following information.
n1=50n1=50, ¯x1=2.32x¯1=2.32, s1=0.68s1=0.68
n2=35n2=35, ¯x2=1.98x¯2=1.98, s2=0.38s2=0.38
For degrees of freedom, use the smaller of
(n1−1)(n1-1) and (n2−1)(n2-1)
tα2tα2 = tinv(α, df)
SE = sqrt((s1s1)^2 / n1n1 + (s2s2)^2 / n2n2)
E = tα2tα2 * SE
CI = (¯x1−¯x2)±E(x¯1-x¯2)±E
Rounded both solutions to 2 decimal places.
Can I have this done in excel please?

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