It is necessary for an automobile producer to estimate the number of miles per gallon achieved by its cars. Suppose that the sample mean for a random sample of 110 cars is 30 miles and assume the standard deviation is 2.4 miles. Now suppose the car producer wants to test the hypothesis that μ, the mean number of miles per gallon, is 33 against the alternative hypothesis that it is not 33. Conduct a test using α=.05 by giving the following: (a) positive critical z score (b) negative critical z score (c) test statistic The final conclustion is A. There is not sufficient evidence to reject the null hypothesis that μ=33. B. We can reject the null hypothesis that μ=33 and accept that μ≠33. Note: You can earn partial credit on this problem.
H0: = 33 , Ha: 33
a)
At 0.05 level, positive critical value = 1.96
b)
At 0.05 level, negative critical value = -1.96
c)
Test statistics
z = ( - ) / ( / sqrt(n) )
= ( 30 - 33) / (2.4 / sqrt(110) )
= -13.11
Since |z| > 1.96 m Reject H0.
Conclusion - We can reject the null hypothesis that μ=33 and accept that μ ≠ 33.
Get Answers For Free
Most questions answered within 1 hours.