Question

The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped and has a mean of 64 and a standard deviation of 9. Using the Empirical rule, what is the approximate percentage of lightbulb replacement requests numbering between 64 and 73?

Do not enter the percent symbol.
ans = %

Answer 1

Answer:-

X ~ normal distribution with mean 64 and standard deviation 9

By using empirical rule

P( < X < )   0.68

= 64 - 9 = 55

= 64 + 9 = 73

P( 55 < X < 73 ) 0.68

since the probability inside of the interval 55, 73 is 0.68

But we want only one sided percentage which is 0.68/2 = 0.34

the approximate percentage of lightbulb replacement requests numbering between 64 and 73 is

Ans = 34 %

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