Let X be the number of cars per minute passing a certain point of some road between 8 A.M. and 10 A.M. on a Sunday. Assume that X has a Poisson distribution with mean 5. Find the probability of observing 4 or fewer cars during any given minute.
Why do I have to use P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) instead of 1P(X=5) for the solution?
Why do I have to use P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) instead of 1P(X=5) for the solution?

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