Consider the following time series data.
Month | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
---|---|---|---|---|---|---|---|
Value | 24 | 13 | 20 | 12 | 19 | 23 | 15 |
(a)
Construct a time series plot.
A time series plot contains a series of 7 points connected by line segments. The horizontal axis ranges from 0 to 8 and is labeled: Month. The vertical axis ranges from 0 to 30 and is labeled: Time Series Value. The points are plotted from left to right at regular increments of 1 month starting at month 1. The points appear to vary randomly between 12 to 24 on the vertical axis. The plot reaches its maximum time series value at month 7.
A time series plot contains a series of 7 points connected by line segments. The horizontal axis ranges from 0 to 8 and is labeled: Month. The vertical axis ranges from 0 to 30 and is labeled: Time Series Value. The points are plotted from left to right at regular increments of 1 month starting at month 1. The points appear to vary randomly between 12 to 24 on the vertical axis. The plot reaches its maximum time series value at month 1.
A time series plot contains a series of 7 points connected by line segments. The horizontal axis ranges from 0 to 8 and is labeled: Month. The vertical axis ranges from 0 to 30 and is labeled: Time Series Value. The points are plotted from left to right at regular increments of 1 month starting at month 1. The points appear to vary randomly between 7 to 19 on the vertical axis. The plot reaches its maximum time series value at month 1.
A time series plot contains a series of 7 points connected by line segments. The horizontal axis ranges from 0 to 8 and is labeled: Month. The vertical axis ranges from 0 to 30 and is labeled: Time Series Value. The points are plotted from left to right at regular increments of 1 month starting at month 1. The points appear to vary randomly between 7 to 19 on the vertical axis. The plot reaches its maximum time series value at month 7.
What type of pattern exists in the data?
The data appear to follow a trend pattern.
The data appear to follow a seasonal pattern.
The data appear to follow a cyclical pattern.
The data appear to follow a horizontal pattern.
(b)
Develop the three-month moving average forecasts for this time series.
Month | Time Series Value |
Forecast |
---|---|---|
1 | 24 | |
2 | 13 | |
3 | 20 | |
4 | 12 | |
5 | 19 | |
6 | 23 | |
7 | 15 |
Compute MSE. (Round your answer to two decimal places.)
MSE =
What is the forecast for month 8?
(c)
Use α = 0.2 to compute the exponential smoothing forecasts for the time series. (Round your answers to two decimal places.)
Month | Time Series Value |
Forecast |
---|---|---|
1 | 24 | |
2 | 13 | |
3 | 20 | |
4 | 12 | |
5 | 19 | |
6 | 23 | |
7 | 15 |
Compute MSE. (Round your answer to two decimal places.)
MSE =
What is the forecast for month 8? (Round your answer to two decimal places.)
(d)
Compare the three-month moving average approach with the exponential smoothing approach using
α = 0.2.
Which appears to provide more accurate forecasts based on MSE?
The exponential smoothing using α = 0.2 provides a better forecast since it has a smaller MSE than the three-month moving average.
The three-month moving average provides a better forecast since it has a smaller MSE than the exponential smoothing using α = 0.2.
The exponential smoothing using α = 0.2 provides a better forecast since it has a larger MSE than the three-month moving average.
The three-month moving average provides a better forecast since it has a larger MSE than the exponential smoothing using α = 0.2.
(a) The time series plot is:
The data appear to follow a horizontal pattern.
(b)
Period | Demand | Forecast | |
Period 1 | 24 | ||
Period 2 | 13 | ||
Period 3 | 20 | ||
Period 4 | 12 | 19 | |
Period 5 | 19 | 15 | |
Period 6 | 23 | 17 | |
Period 7 | 15 | 18 |
MSE = 27.5
The forecast for month 8 = 19
(c)
Period | Demand | Forecast | |
Period 1 | 24 | ||
Period 2 | 13 | 24 | |
Period 3 | 20 | 21.8 | |
Period 4 | 12 | 21.44 | |
Period 5 | 19 | 19.55 | |
Period 6 | 23 | 19.44 | |
Period 7 | 15 | 20.15 |
MSE = 42.15
The forecast for month 8 = 19.12
(d) The three-month moving average provides a better forecast since it has a smaller MSE than the exponential smoothing using α = 0.2.
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