Question

Suppose that in a randomly selected sorority, 52% of members are single, 47% of members attended...

Suppose that in a randomly selected sorority, 52% of members are single, 47% of members attended the last date function, and 20% of members are single and attended the last date function.

1. What is the probability that a randomly selected member is single? Show all work

2. What is the probability that a randomly selected member is not single and did not attend the last date function? Show all work

3. What is the probability that a randomly selected member is not single and attended the last date function?

Homework Answers

Answer #1

let probability of single is P(S) and attending the last date function is P(A)

1)probability that a randomly selected member is single P(S)=0.52 (from above since 52% are single()

2) probability that a randomly selected member is not single and did not attend the last date function =1-P(single or attended the last date function)

=1-P(S u A)

=1-(P(S)+P(A)-P(S n A))

=1-(0.52+0.47-0.2)=0.21

3) probability that a randomly selected member is not single and attended the last date function

=P(A)-P(A n S)

=0.47-0.20

=0.27

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