Question

The time it takes for customers at a Lawrence, Kansas store to check out is normally...

The time it takes for customers at a Lawrence, Kansas store to check out is normally distributed with a mean of 10.2 minutes and a standard deviation of 1.8 minutes. Let the random variable X measure the time it takes for a randomly selected customer at the Lawerence, Kansas store to check out

A) State the distribution of the random variable defined above

B) Compute the probability that a randomly selected customer at the Lawrence, Kansas store will wait less than 7 minutes to check out

C) Compute the probability that a randomly selected customer at the Lawrence, Kansas store will wait between 8 and 9 minutes to check out

D) Compute the probability that a randomly selected customer at the Lawrence, Kansas store will wait longer than 12 minutes to check out

E) Compute and interpret P80

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The board of a major credit card company requires that the mean wait time for customers...
The board of a major credit card company requires that the mean wait time for customers when they call customer service is at most 3.00 minutes. To make sure that the mean wait time is not exceeding the requirement, an assistant manager tracks the wait time of 45 randomly selected calls. The mean wait time was calculated to be 3.40 minutes. Assuming the population standard deviation is 1.45 minutes, is there sufficient evidence to say that the mean wait time...
Observations are made on the time required to check out customers at a supermarket. From a...
Observations are made on the time required to check out customers at a supermarket. From a sample of 36, it takes aisle M an average of six minutes per customer with a standard deviation of three minutes. In the same sample of 36, it takes aisle J an average of eight minutes with a standard deviation of 5 minus. Is the difference in average ties due solely to chance, with a probability of .05 of picking samples with extreme values?
The population mean waiting time to check out of a supermarket has historically been 4 minutes....
The population mean waiting time to check out of a supermarket has historically been 4 minutes. In an effort to reduce the waiting time, you, as store manager, conducted an experiment with infrared cameras that use body heat and in-store software to determine how many lanes should be opened. To test the effectiveness of this process, you selected a random sample of 100 customers and recorded their waiting time. For this sample, the mean waiting time to check out was...
The population mean waiting time to check out of a supermarket has historically been 4 minutes....
The population mean waiting time to check out of a supermarket has historically been 4 minutes. In an effort to reduce the waiting time, you, as store manager, conducted an experiment with infrared cameras that use body heat and in-store software to determine how many lanes should be opened. To test the effectiveness of this process, you selected a random sample of 100 customers and recorded their waiting time. For this sample, the mean waiting time to check out was...
1. (10pts) The board of a major credit card company requires that the mean wait time...
1. (10pts) The board of a major credit card company requires that the mean wait time for customers when they call customer service is at most 3.00 minutes. To make sure that the mean wait time is not exceeding the requirement, an assistant manager tracks the wait time of 45 randomly selected calls. The mean wait time was calculated to be 3.40 minutes. Assuming the population standard deviation is 1.45 minutes, is there sufficient evidence to say that the mean...
Hi! Thanks for taking the time to check out my problem. If you can please answer...
Hi! Thanks for taking the time to check out my problem. If you can please answer as many as possible and I really appreciate your help. Question 1 2 pts The length of time a person takes to decide which shoes to purchase is normally distributed with a mean of 8.21 minutes and a standard deviation of 1.90. Find the probability that a randomly selected individual will take less than 6 minutes to select a shoe purchase. Is this outcome...
3) The amount of time it takes for a grocery clerk to check out a customer...
3) The amount of time it takes for a grocery clerk to check out a customer is evenly distributed between 1 and 5 minutes. a. What kind of distribution is this? b. What is the probability that it will take more than 4 minutes to check out the customer? c. What is the probability that it will take between 2 and 4 minutes? d. What is the probability that it will take exactly 2 minutes? 4) A bank wishing to...
A study shows that at a local bank, the time bank customers spent from the moment...
A study shows that at a local bank, the time bank customers spent from the moment they walk into the bank until they leave the bank can be modeled as a NORMAL random variable, with the mean of 20 minutes and the standard deviation of 4 minutes. (a) If you just walk into the bank, what is the probability that you will stay in the bank longer than 25 minutes? (b) For the next 10 customers walking into the bank,...
No customer wants to wait a long time in a checkout line. A retailer established a...
No customer wants to wait a long time in a checkout line. A retailer established a policy for mean time to check out at 240 seconds. After opening a new location, the retailer asked an analyst to see weather the new store was exceeding this standard (weather customers were waiting too long to check out on average) The analyst took a random sample of 30 customers at the new location and measured the time they had to wait to check...
A customer spending waiting time at a place check-in counter is a random variable with mean...
A customer spending waiting time at a place check-in counter is a random variable with mean 8.2 minutes and standard deviation 1.5 minutes. Suppose that a random sample of n = 49 customers is observed. Find the probability that the average time waiting in line for these customers is: (a) Less than 9.3 minutes (b) Between 5 and 10 minutes (c) Less than 7.5 minutes
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT