A consumer advocate examines whether the longevity of car
batteries (measured in years) is affected by the brand name (factor
A) and whether or not the car is kept in a garage (factor
B). Interaction is suspected. The results are shown in the
accompanying table.
Brand Name of Battery | |||
Kept in Garage? | A | B | C |
Yes | 8, 7, 7 | 7, 6, 7 | 8, 9, 10 |
No | 6, 7, 6 | 5, 6, 4 | 5, 7, 7 |
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a-1. Construct an ANOVA table. (Round intermediate calculations to at least 4 decimal places. Round "SS", "MS" to 4 decimal places and "F", "p-value" to 3 decimal places.)
a-2. At the 5% significance level, Is there
interaction between the brand name and whether a car is
garaged?
b. At the 5% significance level, can you conclude that the average battery lives differ by brand name?
c. At the 5% significance level, can you conclude that the average battery lives differ depending on whether a car is garaged?
Source of variation | Degree of Freedom | Sum of Squares | Mean Sum of Squares | F Value |
Between levels of Factor A | p-1 | |||
Between levels of Factor B | q-1 | |||
Interaction between A and B | (p-1)(q-1) | |||
Error | pq(m-1) | |||
Total | mpq-1 |
Above is the ANOVA table for 2 way analysis of data with m observation per cell.
Where denotes mean of row, denotes mean of column, denotes mean of row and column, refers to mean of all observation and i = 1, 2, 3, ...,p & j = 1, 2, 3, ...., q
In our case, Factor B has 2 levels, ie p = 2 and factor A has 3 levels, q = 3.
Calculation,
required values:
1 | 2 | 3 | |||
1 | 7.3333 | 6.6667 | 9 | 7.6667 | |
2 | 6.3333 | 5 | 6.3333 | 5.8889 | |
6.8333 | 5.8333 | 7.6667 | |||
= 6.778
a1) ANOVA Table
Source of variation | Degree of Freedom | Sum of Squares | Mean Sum of Squares | F Value |
Between levels of Factor A | 1 | 14.222 | 19.692 | |
Between levels of Factor B | 2 | 5.0555 | 6.991 | |
Interaction between A and B | 2 | 1.0555 | 1.462 | |
Error | 12 | 0.7222 | ||
Total | 17 |
a2) No, since the p-value for interaction (0.730) is more than the significance level (0.05)
b) Yes, since the p-value for brand name (0.004) is less than the significance level 0.05.
c) Yes, since the p-value for garage (0.000) is less than the significance level 0.05.
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