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Assume that X is normally distributed with mean of 70 and variance of 9, then compute...

Assume that X is normally distributed with mean of 70 and variance of 9, then compute

P(60<X<75)

Math   Statistics-And-Probability   
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Answer #1

Solution :

Given that ,

mean = = 70

standard deviation = = 9 = 3

P(60 < x < 75) = P[(60 -70)/ 3) < (x - ) /  < (75 -70) / 3) ]

= P(-3.33 < z <1.67)

= P(z < 1.67) - P(z < -3.33)

Using standard normal table

= 0.9525 - 0.0004 = 0.9521

Probability = 0.9521

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