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Let X be a random variable with cdf ?(?) = 0 x<1 1/2(x^2)-x+3/4 1<=x<2 1 x>=2...

Let X be a random variable with cdf ?(?) = 0 x<1

1/2(x^2)-x+3/4 1<=x<2

1 x>=2

(a) (1 pt) Find the median of X

(b) Find the pdf f(x)

(c) (1 pts) Find the variance of X.

Math   Statistics-And-Probability   
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