Problem:
Roll a pair of fair dice. Find the probability that:
a) On an individual roll, the sum is 5 or 11.
b) The first time that you roll a sum of 5 or 11 is on your 7th roll.
c) The 3rd time you roll a sum of 5 or 5 is on your 7th roll.
Solutions from back of textbook:
a) 0.1667
b) 5.58%
c) 3.35%
a)
total number of outcome on two dice =6*6 =36
number of ways sum can be 5 =4 ((1,4),(2,3),(3,2),(4,1))
number of ways sum can be 11 =2 ((6,5),(5,6))
P( sum is 5 or 11)=(4+2)/36 =1/6 =0.1667
b)
The first time that you roll a sum of 5 or 11 is on your 7th roll =P(no 5 or 7 in first 6 rolls and on 7th roll first 5 or 11) =(1-0.1667)^6*0.1667=0.0558 ~ 5.58%
c)P( 3rd time you roll a sum of 5 or 5 is on your 7th roll ) =P(exactly 2 5 or 11 in first 6 rolls and 5 or 11 on 7th roll) =(6C2)*(0.1667)2*(1-0.1667)4*0.1667 =0.2010*0.1667 =0.0335 ~3.35%
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